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10 joules of work is Done to move a charge of -200 coulomb from point A to B. Which of the two pints is at higher potential? What is the P.D between them. If the points are 4 cm apart what is the component of the electric field parallel to the line joining A and B |
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Answer» Answer: A is at a higher potential. The potential difference is -0.05 V. The COMPONENT of the electric field is 1.25 Vm⁻¹ Explanation: Work done=10J Charge(q)(W)=-200 C Now, let potential at A be Vₐ and that at B be Vᵇ. Now, Uₐ=(-200)Vₐ, Uᵇ=(-200)Vᵇ. Work done=Difference in potential ENERGIES (-200)Vᵇ-(-200)Vₐ=10 ⇒ -200Vᵇ+200Vₐ=10 ⇒ Vₐ-Vᵇ=10/200 ⇒ Vₐ-Vᵇ=0.05 Since, Vₐ-Vᵇ>0 Hence, Vₐ>Vᵇ. P.D.=Vᵇ-Vₐ= -0.05 V Component of ELECTRICAL field E= -dV/dR = -(-0.05)/0.04 = 1.25 Vm⁻¹ |
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