10 grams of each O2 , N2 and Cl2 are kept in three bottles. The correct order of arrangment of bottles containingdecreasing number of Molecules.1) O2 , N2 , Cl22) Cl2 , N2 , O23) Cl2 , O2 , N24) N2 , O2 , Cl2

10 grams of each O2 , N2 and Cl2 are kept in three bottles. The corr

1.	10 grams of each O2 , N2 and Cl2 are kept in three bottles. The correct order of arrangment of bottles containingdecreasing number of Molecules.1) O2 , N2 , Cl22) Cl2 , N2 , O23) Cl2 , O2 , N24) N2 , O2 , Cl2
Answer» Option (4) Explanation: HERE IF WE CONVERT All iNTO MOLE AND THEN BY MULTIPLYING IT BY AVAGADRO NUMBER WE CAN FIND OUT WHICH ONE HAS MORE MOLECULES 1 ) 10 GM O2 → 10/32 mole = ( 10 × nA )/32 molecules2 ) 10 of N2 → 10/28 mole = (10×nA ) /28 molecules3 ) 10gm of Cl2 → 10/71.5 = (10×nA)71.5 Thus , On COMPARING N2> O2>Cl2