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10 g of MnO2on reaction with HCI forms 2.24 L of Cl,(g) at NTP, the percentage impurity of MnO2 is MnO2+4HCI = MnCl2+Cl2+ 2H2

Answer» 10 g of MnO2on reaction with HCI forms 2.24 L of Cl,(g) at NTP, the percentage impurity of MnO2 is MnO2+4HCI = MnCl2+Cl2+ 2H2


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