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10 g of ice at `0^@C` is mixed with 100 g of water at `50^@C`. What is the resultant temperature of mixtureA. `31.2^(@)`CB. `32.8^(@)` CC. `36.7^(@)`CD. `38.2^(@)`C |
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Answer» Correct Answer - D `theta_("mix")=(m_(w)theta_(w)-(m_(i)L_(i))/(c_(w)))/(m_(i)+m_(w))` `=(100xx50xx-10xx(80)/(1))/(10+100)` =`38.2^(@)`C |
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