1.

(10) Find the 3 zeroes of the polynomial(x-2)^2-(x+2)^2​

Answer»

p(x) = ( {x - 2)}^{2} - ({x - 2})^{2}

this \: is \: the \: form \: of \: {a}^{2} - {b}^{2}

p(x) = (x - 2 + x + 2)(x - 2 + x + 2)

p(x) = 2x(x - 2 - x - 2)

p(x) = 2x( - 4)

p(x) = 0

- 8x = 0

x = 0

hence

x = 0 \: is \: the \: zero \: of \: the \: polynomial \: p(x)


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