10.D is any point on side AC ofA AABC with AB =AC. Show that CD < BD – InterviewSolution

1.

10.D is any point on side AC ofA AABC with AB =AC. Show that CD < BD

Answer»

Given - AB = AC

To prove -- BD > CD

Proof -- Since AB = AC∠ABC = ∠ACB (By Isosceles Triangle property) ----(i)

Here clearly,∠ABC > ∠CBD ∠ACB > ∠CBD ---from (i)∠DCB > ∠CBDBD > CD (Angle opposite to greater side is greater in a triangle)

Hence Proved.

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