1.

10 class trigonometry evaluate tan square 60 +4cos square 45

Answer»

tan^2 60 + COS^2 45


tan 60 = rt(3) ; cos 45 = 1/(rt(2))


so,


(rt(3))^2 + 1 / ((rt(2))^2)

= 3+(1/2)

(6+1)/2

7/2 = 3 1/2 or 3.5


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