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10. Acar starts from rest with a constant acceleration of 5m/s2 along a straight line .Find the distance travelled by it in the first 2 seconds and the distance travelled by it in the 2nd second.

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tion:u=0a=5m/s^2t=2sv=u+atv=0+5*2v=10M/sS=u*t+1/2*a*t^2S=0+1/2*5*2*2S=10mNow, t=4sS=u*t+1/2*a*t^2S=0+1/2*5*4*4S=40mTherefore, The distance TRAVELLED by it in FIRST 2 seconds is 10m and next two seconds is 40mHope this helps...... Please follow me......



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