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10. a car is travelling with a speed of 36 km/h. the driver applied the brakes and retards the car uniformly. the car is stopped in 5 sec. find (i) the acceleration of car and (ii) distance before it stops after appling breaks?

Answer»

VI = 36 × 1000÷ 3600 = 10m/s

VF -vi = at
A = vf - vi ÷ t
A = 0-10 ÷ 5
A = -2 m/ s2


2AS = vf2 - vi2
S = vf2 - vi2 ÷ 2a
S = (0)2 - (10)2 ÷ 2 × (-2)
S =- 100 ÷ - 4
S = 25 METER

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