1.

10^(-4)g ofgelatin is required to be added to 100 cm^(3)of a standard glodsolutionof justpreventits precipitation by theaddition of 1 cm^(3) of 10% NaCl solutionto it . Hence , the glod numberof gelation in mg is .

Answer»

10
0.01
0.001
0.1

Solution :Gelatin added to `100 cm^(3)` of astandard goldsolutionto preventprecipiation by` 1 cm^(3)` of 10% NaClsolution` = 10^(-4) G = 10^(-1) mg `
Gelation required to be added to `10 cm^(3)` of gold solutionto completelypreventcoagulationby `1 cm^(3)` OF10% NaCl solution` = 10^(-2) mg`
`therefore` By DEFINITION gold numberofgelatin ` = 10^(-2) mg `
` = 0.01 mg`


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