1.

10^(-4)g of gelation is required to be added to 100 cm^(3) of a standard gold solution to just prevent its precipitation by addition of 1 cm^(3) of 10% NaCI solution to it . Hence the gold number of gelation in mg is

Answer»

10
`1.0`
`0.1`
`0.01`

SOLUTION :By defination 100 ML of gold sol REQUIRES `10^(-4)` GM 10 ml of gold sol requires
`=(10)/(100)xx10^(-4) =10^(-5)` gms


Discussion

No Comment Found

Related InterviewSolutions