10^19 electrons flows in a wire30 minites what will becurrent?

1.	10^19 electrons flows in a wire30 minites what will becurrent?
Answer» $\huge\star{\green{\underline{\mathfrak{Answer :-}}}}$ GIVEN: Electrons flowing in the wire = $\tt{10^{19}}$ Time = 30 minutes To FIND: Current or I Solution: Firstly, we will have to find the Charge. We KNOW that, $\boxed{\red{\tt{Q=\pm ne}}}$ USING this formula, $\leadsto\tt{Q = 10^{19} \times (- 1.6 \times 10^{-19} )}$ $\leadsto\tt{Q = 10^{19} \times - 1.6 \times \dfrac{1}{10^{19}}}$ $\huge\leadsto\tt{\underline{\orange{- 1.6\:Coulomb}}}$ Now, finding the current. We know that, $\boxed{\red{\tt{I = \dfrac{Q}{t}}}}$ Using the formula, $\leadsto\tt{I =\dfrac{- 1.6}{30\times 60}}$ $\leadsto\tt{I=\dfrac{-16}{30\times60\times10}}$ $\leadsto\tt{I=\dfrac{-1}{1225}}$ $\leadsto\tt{I=- 0.000816\:A}$ $\huge\leadsto{\boxed{\purple{\underline{\tt{I=-8.16\times10^{-4}\:Ampere}}}}}$ $\rule{200}4$

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$\huge\star{\green{\underline{\mathfrak{Answer :-}}}}$