1. यदि sin 3A = cos (A - 26°), जहाँ 3A एक न्य – InterviewSolution

1.	1. यदि sin 3A = cos (A - 26°), जहाँ 3A एक न्यून कोण है, A का मान ज्ञात कीजिए।
Answer» sin 3A=cos(A −26)⇒cos(90− 3A) = cos(A−26)⇒(90−3A) = (A−26)⇒4A = 116°∴ A = 29°

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