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1+/x+1 Gy‘_+.‘l‘-\/—-x+l & |
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Answer» sqrt(3x +1) + sqrt(x+1)/sqrt(3x+1) - sqrt(x+1) = 4 [sqrt(3x +1) + sqrt(x+1)] ^2/[(3x+1) - (x+1)] = 4 (3x+1 + x + 1) + 2sqrt[(3x+1)*(x+1)] = 2x*4 2sqrt[(3x+1)*(x+1)] = 4x - 2 sqrt[(3x+1)*(x+1)] = 2x - 1 Squaring both sides, we get(3x+ 1)(x +1) = 4x^2 + 1 - 4x3x^2 + 4x + 1 = 4x^2 - 4x + 1x^2 - 8x = 0x(x - 8) = 0x = 0, 8 |
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