1. What volume of 0.5 N NaOH isrequired to neutralize 50 ml 1.5 N HCIs

1.	1. What volume of 0.5 N NaOH isrequired to neutralize 50 ml 1.5 N HCIsolution?O 200 mlO 75 mlO 150 mlO 100 ml
Answer» Answer: No of mili Equivalents = Molarity × n-factor × volume(mili liters) Or No of mili equivalents is also = normality × volume ( mili liters) No of equivalents of Base ADDED = 0.5 × 100 = 50 No of equivalents of acid = 3 × 10 + 1 × 20 = 50 ( since two acids are added so we have to CALCULATE TOTAL equivalents of both acids ) Since milliequivalents of acid and base are equal hence the solution is neutral. Explanation:

1. What volume of 0.5 N NaOH isrequired to neutralize 50 ml 1.5 N HCIsolution?O 200 mlO 75 mlO 150 mlO 100 ml

Answer»

Answer:

No of mili Equivalents = Molarity × n-factor × volume(mili liters)

Or No of mili equivalents is also = normality × volume ( mili liters)

No of equivalents of Base ADDED = 0.5 × 100 = 50

No of equivalents of acid = 3 × 10 + 1 × 20 = 50 ( since two acids are added so we have to CALCULATE TOTAL equivalents of both acids )

Since milliequivalents of acid and base are equal hence the solution is neutral.

Explanation: