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1. Two electrons each moving with a velocity o ms¹ are releasedtowards each other. What will be the closest distance of approachbetween them? |
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Answer» K.E=electrostatic potential at that MOMENT. 0.5*MASS of electron*((10)**6)**2 =9*(10)**9* CHARGE on electron/r. Now CALCULATE the value of r. Explanation:Hope this helps! Do not try to cheat the answer. Just UNDERSTAND the topic. |
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