1) Total number of electron paire= (1)/(2) (number of valence electrons pm electron (for ionic charge) 2) Number of bond electron pairs= number of atoms - 3) Number of electron pairs around central atom= total number of electron pairs - 3 [number atoms (except H)] 4) Number lone pair = (number of central electron pairs - number bond pairs) Read the above method and answer the following questions : Pair of species with same shape and same state of hybridisation of the central atom is :

1) Total number of electron paire= (1)/(2) (number of valence electron

1.	1) Total number of electron paire= (1)/(2) (number of valence electrons pm electron (for ionic charge) 2) Number of bond electron pairs= number of atoms - 3) Number of electron pairs around central atom= total number of electron pairs - 3 [number atoms (except H)] 4) Number lone pair = (number of central electron pairs - number bond pairs) Read the above method and answer the following questions : Pair of species with same shape and same state of hybridisation of the central atom is :
Answer» `PCI_(5) , ICI_(4)^(-)` `NH_(3), H_(2)O` `NH_(3),CIO_(3)^(-)` `ICI_(4)^(-),CIO_(3)^(-)` Answer :C