Saved Bookmarks
| 1. |
1) Three years ago Sonu was 5 years older than Reena. If he is now twice as old as she is, find their present ages.2)Find two consecutive odd numbers whose sum is 56. |
|
Answer»
Let Reena's present age be = 'x' YEARS. Therefore, Sonu's present age will be = '2x' years Reena's age 3 years ago = 'x-3' years Sonu's age 3 years ago = '2x-3' years A/Q, 2x-3 = 5(x-3) 2x-3 = 5x-15 2x-5x = 3-15 [on transposition] -3x = -12 x = -12/-3 Hence, x = 4 Hence,
Reena's present age = 4 years Sonu's present age = 2x years = 2*4 years =8 years This took me a lot of effort Hope it helped you Please mark me as brainliest Please.. |
|