1.

1) The taxi fare after each km when the fare is15 for the first km and 3 for eachadditional km.

Answer»

Fare for 1st km = Rs. 15

Fare for 2nd km = Rs. 15 + 8 = Rs 23

Fare for 3rd km = Rs. 23 + 8 = 31

Here, each subsequent term is obtained by adding a fixed number (8) to the previous term.

Hence, it is an AP



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