1.

1. The sum of the digits of a two digit number is12. If the new number formed by reversing thedigits is greater than the original number by 54,find the original number.

Answer»

Let the digit in one's place be x and tens place be (12-x)

therefre the number will be =10(12-x)+x

120-10x+x

120-9x

120=9x

the number obtined bby interchangin the number will be

10x+12-x

=9x+12

as per given condition,

9x+12=54+120-9x

18x=162

x=9

the number will be

120-9x

120-9(9)

=39



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