1. The potential energy for a force field F is given byU(x, y) = sin (x + y). The force acting on the par-ticle of mass m at

1. The potential energy for a force field F is given byU(x, y) = sin

1.	1. The potential energy for a force field F is given byU(x, y) = sin (x + y). The force acting on the par-ticle of mass m at
Answer» ANSWER:→F(X,y)=−∇U(x,y) F(x,y)=\|∇U(x,y)\|; F(0,π4)=1 Explanation:→F(x,y)=−∇U(x,y) ∇U(x,y)=∂U∂xˆx+∂U∂yˆy=cos(x+y)(ˆx+ˆy) F(x,y)=\|∇U(x,y)\| F(0,π4)=∣∣∇U(0,π4)∣∣=∣∣cos(π4)∣∣\|ˆx+ˆy\| F(0,π4)=1√2√12+12=1unit

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1. The potential energy for a force field F is given byU(x, y) = sin (x + y). The force acting on the par-ticle of mass m at​

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1. The potential energy for a force field F is given byU(x, y) = sin (x + y). The force acting on the par-ticle of mass m at