1.

1. The limit of Balmer series is 36468. The wavelength of first series of this elements will be(A) 65638(B) 36468(C) 72008(D) 10008​

Answer»

ANSWER:

for balmer series,n1=2 ,n2=3,4,.......

WAVELENGTH of balmer series are

1/wavelength =R[1/2^2-1/n^2]

for series LIMIT n2=infinity and WAVE length

for first line n2=3

1/wavelength =R[1/2^2-1/3^2]

1/wavelength = 4/36468×5/36

wavelength = 1312848/20

wavelength of first series of this element is 65638

so ANS is 65638


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