1. The following concentrations were obtained for the formation of NH3, from N2 and H2, at equilibrium at 500K.[N2] = 1.5 x 10^-2M. [H2] = 3.0 x10^-2M and(NH3) = 1.2x10^-2M. Calculate equilibriumconstant.

1. The following concentrations were obtained for the formation of N

1.	1. The following concentrations were obtained for the formation of NH3, from N2 and H2, at equilibrium at 500K.[N2] = 1.5 x 10^-2M. [H2] = 3.0 x10^-2M and(NH3) = 1.2x10^-2M. Calculate equilibriumconstant.
Answer» TION:N2 + 3H2 -- 2NH3 EQUILIBRIUM constant k= [NH3]/[N2][H2]^3k= 1.2×10^-2/1.5×10^-2. (3×10^-2)^3k= 1.2 /1.5.(27×10^-8) k= 4×10^8/5×27k=4×10^8/135 k=0.0296×10^8