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(1+tan21) (1+ tan24)/(I+tan 22 (1+tan23) |
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Answer» [(1+ tan 24°)(1+ tan 21°)] /[(1+ tan 23°)(1+ tan 22°) ][1+tan24+tan21+tan24tan21] [1+tan23+tan22+tan23tan22].......(1)tan(45)=1=tan(24+21) = tan(23+22)tan(A+B) = (tanA+tanB)/(1-tanAtanB)tan(24+21) = (tan24+tan21)/(1-tan24tan21)1*(1-tan24tan21)=tan24+tan211=tan24+tan21+tan24tan21....(2)similarly, tan23+tan22+tan23tan22=1......(3)substituting equation 2 & 3 in equation 1[1+1] /[1+1]=1 |
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