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1 Solve x ^-3x -16x +48= 0, given thatthe sum of two roots is zero. |
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Answer» Factor it by grouping. x^3 - 3x^2 - 16x + 48 = x^2(x-3) - 16(x-3) = (x-3)(x^2-16) = (x-3)(x+4)(x-4) Set the product equal to zero, and apply zero product property. Zeros are -4, 3, 4. tq |
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