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(1) Solve the following simultaneous equations:3x-4y 10; 4x+3y 5 |
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Answer» let, 3x-4y = 10 ----------> {1} 4x+3y = 5 ------------> {2} {1} × 3 = 9x - 12y = 30 {2} ×4 = 16x + 12y = 20===================== 25x = 50 x = 50/25 x = 2 therefore , x = 2 now place x in eq 1 (3×2) - 4y = 10 6 - 4y = 10 -4y = 4 y = (-1) so , x = 2y = (-1) Hit like if you find it useful! thank you for answer |
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