1.

(1 + sinθ)(1-sina)cosig-I-sinzgcos, θ1-coseV1-cose(1 + cos0) (1 + cost)Vcos6) (+cos×1+cos

Answer»

√1+cosx/√1-cosx= √(1+cosx)*(1+cosx)/√(1-cos²x)= √(1+cosx)²/√sin²x= (1+cosx)/sinx= 1/sinx +cosx/sinx= cosecx + cotx



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