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(1-sinA-cosA)^2 = 2(1-sinA) ( 1-cosA) |
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Answer» (1-SINA-COSA)²=2(1-sinA) ( 1-cosA) LHS (1-sinA-cosA)² (1)²+(-sinA)²+(-cosA)²+2(1)(-sinA)+2(-sinA)(-cosA)+2(1)(-cosA) 1+sin²A+cos²A -2sinA+2sinAcosA-2cosA 1+1 -2sinA+2cosAsinA-2cosA 2-2sinA+2cosAsinA-2cosA 2(1-sinA+sinAcosA-cosA) RHS 2(1-sinA) ( 1-cosA) 2(1(1-cosA)-sinA(1-cosA)) 2(1-cosA-sinA+sinAcosA) therefore, LHS=RHS hope it helps you and don't forget to follow me
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