Saved Bookmarks
| 1. |
1-sin60°÷cos60°=tan60°-1÷tan60°+1 |
| Answer» Sin 60 =\xa0√3/2cos 60 = 1/2tan 60 =\xa0√3lhs = (1-sin 60) /cos 60= (1-√3/2) /(1/2)\xa0= 2-√3rhs = (tan60 -1) /(tan60 +1)= (√3-1)/(√3 +1)= (√3-1) (√3 -1)/[(√3+1)(√3-1)]=(√3 -1)²/[(√3)² -1²]= (3+1 -2√3) /(3-1)=(4 -2√3)/2=2-√3LHS = RHShence proved | |