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1+sin2x - cos2x/1+sin2x + cos2x= tanx |
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Answer» cos^2x+sin^2x +sin2x- (cos^2x-sin^2x)÷ cos^2x+sin^2x+sin2x +cos^2x-sin^2xUsing identity cos^2x+sin^2x=1 and cos2x=cos^2x-sin^2x.On simplifying we get 2sin^2x +sin2x÷2cos^2x+sin2x= 2sinx(sinx+cosx)÷2cosx(cosx+sinx)=sinx/cosx = tanx 0 |
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