1+sin theta/1-sin theta= (sec theta+tan theta) ²

1.	1+sin theta/1-sin theta= (sec theta+tan theta) ²
Answer» $LHS = \frac{(1+sin \theta )}{(1-sin \theta )}$ $= \frac{(1+sin \theta )(1+sin \theta)}{(1-sin \theta )(1+sin \theta)}$ $= \frac{(1+sin \theta )^{2}}{1^{2}-(sin \theta )^{2}}$ $= \frac{(1+sin \theta )^{2}}{cos \theta ^{2}}$ $= \Big( \frac{(1+sin \theta )}{cos \theta}\Big)^{2}$ $= \Big( \frac{1}{cos \theta }+ \frac{sin \theta }{cos \theta } \Big)^{2}$ $= ( sec \theta + tan \theta )^{2}$ $= RHS$ THEREFORE., $\red{ \frac{(1+sin \theta )}{(1-sin \theta )}}$ $\green {= ( sec \theta + tan \theta )^{2} }$ •••♪

Answer»

$LHS = \frac{(1+sin \theta )}{(1-sin \theta )}$