1.

1.Show that the number 8" can never end with a digit zero for any natural number n.

Answer»

For a number to end with the digit 0 it's prime factorization should have 2 and 5 as a common factor.

here 8^n = (2*4)^n doesn't have 5 in its prime factorization.

Therefore 8^n cannot end with the digit 0.



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