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1.Show that the number 8" can never end with a digit zero for any natural number n. |
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Answer» For a number to end with the digit 0 it's prime factorization should have 2 and 5 as a common factor. here 8^n = (2*4)^n doesn't have 5 in its prime factorization. Therefore 8^n cannot end with the digit 0. |
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