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1 + sec A sin Asec A C [Hint: Simplify LHS and RHS separa1 - cos At A using the identity cose

Answer»

(1+secA)/secA = sin²A/(1-cosA)solving LHS(1+secA)/secA=1/secA + 1=cosA+1

soling RHSsin²A/(1-cosA)=(1-cos²A)/(1-cosA)=1+cosA

LHS=RHS



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