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1.Rohan bought a rhombus shaped field,whose diagonals are 2400 m and 1000 m.Rohan wants to fence it but don’t know the length of its boundary 1.1.Which of the following is the length of side of fieldA ) 1200 metresB ) 1300 metresC ) 1400 metresD ) 1500 metres1.2 What will be the cost of fencing the length of boundary of the field,If cost of fencing is 70 rupees per metre ?A ) 3,36,000 RupeesB ) 3,56,000 RupeesC ) 3,64,000 RupeesD ) 1,05,000 Rupees1.3 What is the area of land Rohan bought ?A) 12,00,000m^2B ) 6,00,000 m^2C ) 9,00,000 m^2D ) 3,00,000 m^21.4 If the rate of land is Rs. x per square m, the cost will be_____Rs. 2400000xRs. 1300000Rs. 1200000Rs. 1200000x1.5 Which of the following statement is false?All the squares are rhombus.All the rhombus are squares.Diagonals bisects perpendicularly in squares.Diagonals bisects perpendicularly in rhombus.

Answer»

Answer:

a) let ABCD be the sides and point O at which the diagonals meet

AO = 500 m

OC = 500 m

(Diagonals bisect each other)

BO = 1200 m

OD = 1200 m

(Diagonals bisect each other)

Each forms a right TRIANGLE inside so we can use Pythogorean theorm

a² + b² = c²

500² + 1200² = c²

=>2500 + 14400 = c²

=>16900 = c²

=> c = √16900

=> c = 130

b) perimeter = 4s

1 side = 130 m

Per METER = 70 rs

Perimeter = 130 x 4

                = 520 m

Cost = 520 x 70

       = 36400 rs

c) AREA of rhombus = pq

/2

p = 2400 q = 1000

2400x1000/2 = 2400000/2

= 1200000 m²

Hope its helpful :D

Step-by-step explanation:



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