Saved Bookmarks
| 1. |
1.Rohan bought a rhombus shaped field,whose diagonals are 2400 m and 1000 m.Rohan wants to fence it but don’t know the length of its boundary 1.1.Which of the following is the length of side of fieldA ) 1200 metresB ) 1300 metresC ) 1400 metresD ) 1500 metres1.2 What will be the cost of fencing the length of boundary of the field,If cost of fencing is 70 rupees per metre ?A ) 3,36,000 RupeesB ) 3,56,000 RupeesC ) 3,64,000 RupeesD ) 1,05,000 Rupees1.3 What is the area of land Rohan bought ?A) 12,00,000m^2B ) 6,00,000 m^2C ) 9,00,000 m^2D ) 3,00,000 m^21.4 If the rate of land is Rs. x per square m, the cost will be_____Rs. 2400000xRs. 1300000Rs. 1200000Rs. 1200000x1.5 Which of the following statement is false?All the squares are rhombus.All the rhombus are squares.Diagonals bisects perpendicularly in squares.Diagonals bisects perpendicularly in rhombus. |
|
Answer» Answer: a) let ABCD be the sides and point O at which the diagonals meet AO = 500 m OC = 500 m (Diagonals bisect each other) BO = 1200 m OD = 1200 m (Diagonals bisect each other) Each forms a right TRIANGLE inside so we can use Pythogorean theorm a² + b² = c² 500² + 1200² = c² =>2500 + 14400 = c² =>16900 = c² => c = √16900 => c = 130 b) perimeter = 4s 1 side = 130 m Per METER = 70 rs Perimeter = 130 x 4 = 520 m Cost = 520 x 70 = 36400 rs c) AREA of rhombus = pq /2 p = 2400 q = 1000 2400x1000/2 = 2400000/2 = 1200000 m² Hope its helpful :D Step-by-step explanation: |
|