1: Prove that sin⁶0 + cos ⁶0 + 3sin²0 cos²0 = 1

1.	1: Prove that sin⁶0 + cos ⁶0 + 3sin²0 cos²0 = 1
Answer» we KNOW , a^3 + b^3 = (a + b)^3 - 3 AB(a+b) here, L.H.S =sin^6O + cos^6O + 3sin^2O.cos^2O = (sin^2O)^3 + (cos^2O)^3 + 3sin^2O.cos^2O = (sin^2O+ cos^2O)^3 - 3sin^2O.cos^2O + 3sin^2O.cos^2O = 1 = R.H.S PROVED

Answer»

we KNOW ,

a^3 + b^3 = (a + b)^3 - 3 AB(a+b)

here, L.H.S

=sin^6O + cos^6O + 3sin^2O.cos^2O

= (sin^2O)^3 + (cos^2O)^3 + 3sin^2O.cos^2O

= (sin^2O+ cos^2O)^3 - 3sin^2O.cos^2O + 3sin^2O.cos^2O

= 1 = R.H.S PROVED

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1: Prove that sin⁶0 + cos ⁶0 + 3sin²0 cos²0 = 1​

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1: Prove that sin⁶0 + cos ⁶0 + 3sin²0 cos²0 = 1