1)=One of the angles of triangle is 65° ..If the difference of the remaining angles is 35°.then remaining angles are 75° and 40° .Justify!2)= An exterior angle of triangle is 105° and it's two interior opposite angles are equal .Each of these equals angles is (52×1/2)°Justify!

1)=One of the angles of triangle is 65° ..If the difference of the re

1.	1)=One of the angles of triangle is 65° ..If the difference of the remaining angles is 35°.then remaining angles are 75° and 40° .Justify!2)= An exterior angle of triangle is 105° and it's two interior opposite angles are equal .Each of these equals angles is (52×1/2)°Justify!
Answer» A+b+65=180(Angle sum PROPERTY) a+b=115(1 equation) a-b=35(2equation) ADD 1&2 a+b=115 a-b=35 ----------- 2a=150 a=75 put the VALUE of 'a' in equation 1 a+b=115 b=115-75 b=40 Therefore a=75,b=40 verified

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1)=One of the angles of triangle is 65° ..If the difference of the remaining angles is 35°.then remaining angles are 75° and 40° .Justify!2)= An exterior angle of triangle is 105° and it's two interior opposite angles are equal .Each of these equals angles is (52×1/2)°Justify!

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