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1 mole of propane ( C3 H8 ) on combustion at STP gives 'A' kilojoules of heat energy . Calculate the heat liberated when 2.4 liter of propane undergoes combustion at STP |
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Answer» ong>ANSWER: calculate the heat liberated when 2.4 litres of propane on COMBUSTION at STP. so, one mole of propane = 44g. so, 89.2 ml of propane burns to give A kj of energy. = 26.9 A kj of energy. Explanation: |
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