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1 mole of a gas AB3 present in 10 L container dissociates into AB2(g) and B2(g).2AB3(g)⇌2AB2(g)+B2(g)If the degree of dissociation of AB3 is 80%, then final pressure at 600 K is:(Given R=0.082 L atm K−1mol−1)

Answer» 1 mole of a gas AB3 present in 10 L container dissociates into AB2(g) and B2(g).

2AB3(g)2AB2(g)+B2(g)

If the degree of dissociation of AB3 is 80%, then final pressure at 600 K is:

(Given R=0.082 L atm K1mol1)


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