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`1` mol of an ideal gas undergoes different thermodynamical process in `P-V` digram given below : If temperature at point `C` is `T K` then :A. Temperature at point `A` is `T K`.B. Temperature at point `A` is `2T K`.C. Temperature at point `B` is `T K`.D. Temperature at point `B` is `2T K`. |
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Answer» Correct Answer - B::D Process `CA` is isochoric `P_(A) = 2P_(C)` so `T_(A) = 2T` And process `AB` is isothermal `T_(A) = T_(B) = 2T` |
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