1- (log base xyz of x + log base xyz of y) = ?

1.	1- (log base xyz of x + log base xyz of y) = ?
Answer» Answer: There is a logarithmic property that is very useful to know: logb(a)=1loga(b) . This can be PROVEN using the change of base FORMULA, but it MEANS that 1logxy(xyz)=logxyz(xy) . Likewise, 1logyz(xyz)=logxyz(yz) and 1logzx(xyz)=logxyz(zx) . This means that the original expression can be WRITTEN as logxyz(xy)+logxyz(yz)+logxyz(zx) . Adding the LOGARITHMS gives us logxyz(xy×yz×xz) =logxyz(x2y2z2) =logxyz((xyz)2) =2 .

Answer»

Answer:

There is a logarithmic property that is very useful to know: logb(a)=1loga(b) . This can be PROVEN using the change of base FORMULA, but it MEANS that 1logxy(xyz)=logxyz(xy) . Likewise, 1logyz(xyz)=logxyz(yz) and 1logzx(xyz)=logxyz(zx) .

This means that the original expression can be WRITTEN as logxyz(xy)+logxyz(yz)+logxyz(zx) .

Adding the LOGARITHMS gives us logxyz(xy×yz×xz)

=logxyz(x2y2z2)

=logxyz((xyz)2)

=2 .

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1- (log base xyz of x + log base xyz of y) = ?​

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1- (log base xyz of x + log base xyz of y) = ?