1.

1 litre solution containing 4.5 milimoles of Cr_(2)O_(7)^(-) and 15 milimoles of Cr^(3+) shows a pH of 2.0. The potential of the reduction half reaction is approximately xV. Then [x] is ……… where [ ] is GIF.(E^(@) of Cr_(2)O_(7)^(2-)//Cr^(3+) is 1.33V)

Answer»


Solution :`14H^(+)+Cr_(2)O_(7)^(--)+6e^(-)to 2Cr^(3)+7H_(2)O`
`E_(Cr_(2)O_(7)^(-)//CR^(3+))=1.33+0.059/6"LOG"_(10)(4.5xx10^(-31))/(2.25xx10^(-4))`
`= 1.33+ 0.059/5 "log"_(10)(2xx10^(-27))`
`=1.06`
`=1V`


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