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1 Kg of water (CP = 0.5 J/Kg^oC) is pumped to a height of 0.5 m, work done by the motor is 40 J/Kg, and heat liberated by it is 10 J/Kg, what is the final temperature of water if the initial temperature was 10^oC?(a) 10^oC(b) 30^oC(c) 40^oC(d) 60^oC |
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Answer» Correct choice is (d) 60^oC The explanation: ∆U = Q + W – m (∆H + ∆PE + ∆KE), => 0 = – 10 + 40 – 1*(∆H + 10*0.4), => ∆H = 25 J/Kg, => 25 = 0.5(T – 10), => T = 60^oC. |
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