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[(1-iota)(2-iota)(3-iota)]/(1+iota) |
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Answer» -5i-5 Step-by-step explanation: answer: first we will SOLVE values in [ ] (1-i)(2-i)(3-i)= -10i -10i/1+i (-10i/1+i) x( 1-i)/(1-i) multiply with a CONJUGATE term -10i+10i^2/(1-i^2) -10i+10(-1)/1-(-1) -10i-10/2 -5i-5 |
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