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1. In the figure, Q is the centreof the circle and PM and PNare tangent segments to thecircle. If ZMPN = 40°,find ZMON. |
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Answer» nice, all members wrote correctly Given, angle MPN=40 degreePM and PN are tangentsSince PM and PN are Tangents, angle QMP=90 degreeangle QNP=90 degreeIn quad. QMPN, angle(MPN+PNQ+NQM+QMP)=360 degree (sum of all angles of a quad. is 360 degree) or 40+90+90+MQN=360 degreeso, angle MQN=140 degree. MNQP IS QUADRILATERAL SO ITS SUM OF ALL ANGLES IS 360 ,AND ANGLE MAND ANGLE N IS 90 DEGREE SO 180 AND 40 so 220degree and 360 -220 IS OUR ANGLE Q SO IT IS 140 degree |
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