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1. In figure, if AD -73 m, then find BC604 |
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Answer» In ∆ ABD,tan(30°) = AD/BD 1/(√3) = 7√3/BD BD = 7 × 3 cm = 21 cm In ∆ADC, tan(60°) = AD/DC √3 = AD/DC DC = 7√3/√3 DC = 7 cm So, BC = BD + DC = 21 cm + 7 cm = 28 cm |
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