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1) In a right angle triangle, the difference between areas of squares drawn onperpendicular sides of triangles is 7 sq.cm., and the area of square drawn onhypotenuse is 25 sq.cm. Find sides of triangle.​

Answer»

Correct QUESTION :- In a right angle triangle, the areas of square drawn on perpendicular sides of a triangle is 49 Sq. cm. and the areas of square drawn on HYPOTENUSE is 625 Sq. cm. find the sides of the triangle ?

SOLUTION :-

we know that,

side of square = √(Area)

so,

→ Area of square drawn on perpendicular side = 49 cm²

→ Perpendicular side = √(49) = 7 cm.

SIMILARLY,

→ Area of square drawn on hypotenuse side = 625 cm²

→ Perpendicular side = √625 = 25 cm.

then,

→ Base = √[(Hypotenuse)² - (Perpendicular)²]

→ Base = √[(25)² - (7)²]

→ Base = √(625 - 49)

→ Base = √576

→ Base = 24 cm.

therefore, the sides of the triangle are 7 cm , 24 cm and 25 cm.



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