1.In a race athlete takes 3 rounds of a circular track of length 200m

1.	1.In a race athlete takes 3 rounds of a circular track of length 200m in 2 hrs 45 minutes.(i) Calculate the ratio of displacement and distance covered.(ii) Is the motion uniform or non-uniform. (iii) Calculate average speed and average velocity.
Answer» Given: In a race athlete takes 3 ROUNDS of a circular track of length 200m in 2 hrs 45 minutes. To find: The ratio of displacement and distance covered. Is the motion uniform or non-uniform. Calculate average speed and average velocity. Calculation: 1st part : The athlete completed three rounds of the circular track in the specified time and hence his starting POINT and stopping point are same. As a RESULT, his Displacement is Zero Distance = 3 × 200 = 600 m $\boxed{ \sf{ \dfrac{displacement}{distance} = \dfrac{0}{600} = 0}}$ 2nd part: The motion is Uniform Circular Motion because the athlete MOVES with constant speed. 3rd part: $\boxed{ \sf{avg. \: speed = \dfrac{600}{120 + 45} = 3.63 \: m \: {min}^{ - 1} }}$ $\boxed{ \sf{avg. \: velocity = \dfrac{0}{120 + 45} = 0 \: m \: {min}^{ - 1} }}$

1.In a race athlete takes 3 rounds of a circular track of length 200m in 2 hrs 45 minutes.(i) Calculate the ratio of displacement and distance covered.(ii) Is the motion uniform or non-uniform. (iii) Calculate average speed and average velocity.

Answer»

Given:

In a race athlete takes 3 ROUNDS of a circular track of length 200m in 2 hrs 45 minutes.

To find:

The ratio of displacement and distance covered.
Is the motion uniform or non-uniform.
Calculate average speed and average velocity.

Calculation:

1st part :

The athlete completed three rounds of the circular track in the specified time and hence his starting POINT and stopping point are same. As a RESULT, his Displacement is Zero

Distance = 3 × 200 = 600 m

$\boxed{ \sf{ \dfrac{displacement}{distance} = \dfrac{0}{600} = 0}}$

2nd part:

The motion is Uniform Circular Motion because the athlete MOVES with constant speed.

3rd part:

$\boxed{ \sf{avg. \: speed = \dfrac{600}{120 + 45} = 3.63 \: m \: {min}^{ - 1} }}$

$\boxed{ \sf{avg. \: velocity = \dfrac{0}{120 + 45} = 0 \: m \: {min}^{ - 1} }}$