1. In a pen holder, there are some pens. Out of the total pens, 8 are

1.	1. In a pen holder, there are some pens. Out of the total pens, 8 are red, 7 are blue, and the restare green. If the probability of getting a red pen is 2, then find the total number of pens inthe penholder and the probability of getting a green pen.A die is rolled 8 times. What is th5
Answer» Answer, (1) (a)LET x be the GREEN pens, so the total pens are =8+7+x=15+x Red pens are =8 , A PROBABILITY can not be more than 1 so i am guessing it is (1/2) not 2, Alright P(red)=1/2=N(red)/N(total)=(8)/(15+x) 15+x=16 x=16-15=1 So the total number of pens are =7+8+1=16 (b) Probability of Getting a green pen is P(green)=N(green)/N(Total)=1/16 Next question is incomplete

1. In a pen holder, there are some pens. Out of the total pens, 8 are red, 7 are blue, and the restare green. If the probability of getting a red pen is 2, then find the total number of pens inthe penholder and the probability of getting a green pen.A die is rolled 8 times. What is th5

Answer»

Answer, (1)

(a)LET x be the GREEN pens, so the total pens are =8+7+x=15+x

Red pens are =8 , A PROBABILITY can not be more than 1 so i am guessing it is (1/2) not 2, Alright

P(red)=1/2=N(red)/N(total)=(8)/(15+x)

15+x=16

x=16-15=1

So the total number of pens are =7+8+1=16

(b)

Probability of Getting a green pen is P(green)=N(green)/N(Total)=1/16

Next question is incomplete