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1) If the velocity of the body in motion of a particle is governed by the equation V= 2t3+(-3t)2+2t+2 Then find out the acceleration of the particle at t=4s and calculate the distance covered during the interval 3 sec to 6sec​

Answer»

ANSWER:

ACCELERATION at t=4 SEC is 74ms^-2

Explanation:

EXPLAINATION is above in PIC



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