1.

1. Identify the substance oxidised, substance reduced, oxidising agent and reducing agent in the reaction:Cl2 + 2l- → 2Cl- + l22. Calculate the oxidation number of underlined elements in the following compounds:(i) K2Cr2O7 (ii) HHO3

Answer»

1. Cl2 is reduced, therefore Cl2 is the oxidising agent. I’ is oxidised, therefore I” is the reducing agent.

(i) K2Cr2O7

(+1 × 2) + 2x +(-2 × 7) = 0 

+2 + 2x – 14 =0 

2x – 12 =0 

2x = 12 

x = +6 

(ii) HHO3 

(+1 × 1) + x + (-2 × 3) = 0 

1+ x – 6 = 0 

x – 5 = 0 

x = +5



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