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1. Identify the substance oxidised, substance reduced, oxidising agent and reducing agent in the reaction:Cl2 + 2l- → 2Cl- + l22. Calculate the oxidation number of underlined elements in the following compounds:(i) K2Cr2O7 (ii) HHO3 |
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Answer» 1. Cl2 is reduced, therefore Cl2 is the oxidising agent. I’ is oxidised, therefore I” is the reducing agent. (i) K2Cr2O7 (+1 × 2) + 2x +(-2 × 7) = 0 +2 + 2x – 14 =0 2x – 12 =0 2x = 12 x = +6 (ii) HHO3 (+1 × 1) + x + (-2 × 3) = 0 1+ x – 6 = 0 x – 5 = 0 x = +5 |
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